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Consider a variable which measures "years of experience" among a sample of police officers. This variable has a mean of 10.8 and a standard deviation of 7.2. One officer has 15 years of experience. If we were to convert this variable into a z-score, the value for this particular officer would be...

Guest Jun 17, 2017
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z-score  =  ( score - average ) / ( standard deviation )

z-score  =  (15 - 10.8) / 7.2  =  0.5833

geno3141  Jun 17, 2017

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