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# help

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Segment $$s_1$$ has endpoints at $$(3+\sqrt{2},5)$$ and (4,7). Segment $$s_2$$ has endpoints at $$(6-\sqrt{2},3)$$ and (3,5). Find the midpoint of the segment with endpoints at the midpoints of $$s_1$$ and $$s_2$$ . Express your answer as (a,b).

Jan 15, 2019

#1
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Okay, here we go: Let's start by finding the midpoint of $$s_1.$$ We have $$(\frac{7+\sqrt{2}}{2}, 6)$$ and $$(\frac{9-\sqrt{2}}{2}, 4).$$ Now, we take the midpoint of these two numbers, yielding us with $$\boxed{(4, 5)}.$$

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Jan 15, 2019

Okay, here we go: Let's start by finding the midpoint of $$s_1.$$ We have $$(\frac{7+\sqrt{2}}{2}, 6)$$ and $$(\frac{9-\sqrt{2}}{2}, 4).$$ Now, we take the midpoint of these two numbers, yielding us with $$\boxed{(4, 5)}.$$