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Segment \(s_1\) has endpoints at \((3+\sqrt{2},5)\) and (4,7). Segment \(s_2\) has endpoints at \((6-\sqrt{2},3)\) and (3,5). Find the midpoint of the segment with endpoints at the midpoints of \(s_1\) and \(s_2\) . Express your answer as (a,b).

 Jan 15, 2019

Best Answer 

 #1
avatar+4299 
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Okay, here we go: Let's start by finding the midpoint of \(s_1.\) We have \((\frac{7+\sqrt{2}}{2}, 6)\) and \((\frac{9-\sqrt{2}}{2}, 4).\) Now, we take the midpoint of these two numbers, yielding us with \(\boxed{(4, 5)}.\)

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 Jan 15, 2019
 #1
avatar+4299 
+2
Best Answer

Okay, here we go: Let's start by finding the midpoint of \(s_1.\) We have \((\frac{7+\sqrt{2}}{2}, 6)\) and \((\frac{9-\sqrt{2}}{2}, 4).\) Now, we take the midpoint of these two numbers, yielding us with \(\boxed{(4, 5)}.\)

tertre Jan 15, 2019

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