Find the smallest positive integer that is exactly half the sum of its proper divisors.
Find the smallest positive integer that is exactly half the sum of its proper divisors.
I didn't know what a "proper divisor" is, so I looked it up. If you use the definition given at wolfram.com, the problem can't be solved. Wolfram defines proper divisor as follows: "A positive proper divisor is a positive divisor of a number, excluding itself. For example, 1, 2, and 3 are positive proper divisors of 6, but 6 itself is not."
6 would work if you didn't have to exclude itself. Divisors 1 & 2 & 3 & 6 added up equals 12 and 6 is half of that, but Wolfram says 6 cannot be counted as a proper divisor of 6.
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