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Let \(f(x) = (x+2)^2-5\). If the domain of \(f\) is all real numbers, then \(f\) does not have an inverse function, but if we restrict the domain of \(f\) to an interval \( [c,\infty)\), then \(f\) may have an inverse function. What is the smallest value of \(c\) we can use here, so that \(f\) does have an inverse function?

 Aug 7, 2019

If we restrict the domain from the vertex to positive infinity then f(x) will be a bijection.

We can read the vertex off as x=-2, so we restict the domain as -2 <= x < +infinity

 Aug 7, 2019

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