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Thanks!

 Apr 13, 2019
 #1
avatar+106519 
+1

If the perimeter of one of the equilateral  triangles is 1, then one side = 1/3

And the area of one of these triangles = (1/2(1/3)^2 * √3/2  =  √3/36 units^2

 

Also.....the height, h,  of one of these triangles can be found as

 

tan 60 =  h/ (1/2 base)

√3 = h (!/2 * 1/3)

√3 = h (1/6)

√3/6  = h

 

And this will also be the height of the middle parallelogram

And the area of a parallelogram  =  base * height

So

 

Area of parallelogram  = Area of one triangle....so.....

 

√3/36 =  base * (√3/6)   

1/36 = base * 1/6   

1/6  = base of parallelogram

 

So....the perimeter of the parallelogram  =

 

2(1/3 + 1/3 + 1/6)  =

 

2 ( 2/3 + 1/6) =

 

2 ( 4/6 + 1/6) =

 

4 (5/6)

 

10 / 6 units

 

 

 

cool cool cool

 Apr 13, 2019
 #2
avatar+200 
+1

Thanks CPhill! You really helped my understand that question!

 Apr 13, 2019
 #3
avatar+106519 
+1

OK....that one was a little difficult!!!

 

cool cool cool

CPhill  Apr 13, 2019
 #4
avatar+200 
+2

Yeah! It stumped me too!

Rudram592  Apr 13, 2019

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