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1. Find the equation of the axis of symmetry of the graph of y = (x + 3)^2 - 5

2. Find the equation of the axis of symmetry of the parabola.
[asy]
unitsize(0.5 cm);

real f(real x) {
return (3 - (x - 2)^2/4);
}

int i;

for (i = -5; i <= 5; ++i) {
draw((i,-5)--(i,5),gray(0.7));
draw((-5,i)--(5,i),gray(0.7));
}

draw((-5,0)--(5,0));
draw((0,-5)--(0,5));

draw(graph(f,-3.6,5), red);

label("$x$", (5,0), NE);
label("$y$", (0,5), NE);
[/asy]
write the answer as an equation

 Feb 9, 2021
 #1
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1) this is parabola in vertex form     vertex = (-3,-5)      axis of sym   x = -3

 Feb 9, 2021
 #2
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2) Axis of symmetry is x = 4.

 Feb 9, 2021

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