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A merchant bought some oranges at the rate of 3 for 16 cents.  He bought twice as many oranges at the rate of 4 for 21 cents.  To make a profit of 20%, based on his investment, he sold them all at the rate of 3 for k cents.  Find k.

 Dec 6, 2019
 #1
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Let the number of organges he first bought  =  N.....so the total cost of these  = N (16/3)

So the number that he bought in the second instance  =  2N....so the total cost of these = 2N (21/4)

And  the revenue he makes  =  3N(k/3)

 

So

 

1.2  [  cost of goods sold  ]  = total revenue

 

1.2  [ N (16/3)   +  2N (21/4) ]  =   3N(k/3)       divide through by N

 

1.2 ( 16/3  + 2(21/4) ]  =   k

 

1.2 [ 16/3  + 21/2]  = k

 

(6/5) [ 32  + 63 ] / 6  = k

 

[ 32 + 63 ] / 5   =  k

 

95 / 5  =  k

 

19   = k

 

cool cool cool

 Dec 6, 2019

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