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How much pure water must be mixed with 3 pints of 60% developer to produce a mixture that is 23% developer?

 Apr 7, 2020
 #1
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Note that  pure  water  = 0%  developer

 

So.....call the amount of  pure water, W    and we have that

 

0% (W)  +  .60 (3)  =  .23 ( W + 3)     simplify

 

1.8  = .23W   + .69       subtract .69 from both sides

 

1.11=  .23W             divide  both  sides  by .23

 

111/23 =  W ≈  4.826 pints

 

 

cool cool cool

 Apr 7, 2020

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