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Factor completely: x^8 - 12x^4 - 64.

 Jun 10, 2020
 #1
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Let x = x^4

 

x^2 - 12x-64

(x-16)(x+4)                      put x^4 back in

(x^4-16)(x^4+4)               let x = x^2

(x^2-16)(x^2+4)

(x-4)(x+4)(x^2+4)             put x^2 back in

(x^2-4)((x^2+4)(x^4+4)

(x-2)(x+2)(x^2+4)(x^4+4)    

(x-2)(x+2)(x^2+4)(x^2+2x+2)(x^2-2x+2)       I think this is as far as I can go with it....anyone else? 

 Jun 10, 2020

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