Write 45 in the form k√5, where k is an integer
Can someone explain how to do this.
The prime factorization of 45 is 5*3*3.
So, √45 can be re-written as √(5*3*3). Beacuse of order of operations, this yeilds exactly the same value as √(3^2) * √(5) .
The square root of 3 squared (√(3^2)) is 3.
Now our expression is 3√(5).
Therfore, k must be equal to 3
+129842 k cannot be an integer because this implies that a rational quantity - 45 - would equal an irrational quantity - k√5
If this is what you meant, we can find "k" thusly :
45 = k √5 divide both sides by √5
45 / √5 = k
However......if you meant √45, then the guest's answer is correct.....
