Compute f '(a) algebraically for the given value of a. f(x) = 6x2 + x; a = 1
\(f(x) = 6x^2 + x\\ f'(x) =12x + 1\\ f'(a) =12a + 1\\ f'(1) =12*1 + 1\\ f'(1) =13\\\)
To do this question, differentiate f(x) first.
\(f(x) = 6x^2+x\)
\(\frac{d}{dx}f(x) = f'(x) = 12x + 1\)
\(f'(a) = 12a +1\)
When a = 1,
\(f'(1) = 12(1) + 1 = 13\)
