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-\frac{1}{2}\left(3x+4\right)^'=11

 Aug 21, 2017
 #1
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-\frac{1}{2}\left(3x+4\right)^'=11

Maybe you mean

-\frac{1}{2}\left(3x+4\right)=11

 

\(-\frac{1}{2}\left(3x+4\right)=11\\ 3x+4=-22\\ 3x=-26\\ x=-8\frac{2}{3} \)

.
 Aug 21, 2017

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