What is the area, in square units, of a regular hexagon inscribed in a circle whose area is \(324\pi\) square units? Express your answer in simplest radical form.
Not too difficult.....the radius of the circle, r = the side of the hexagon, s...so
324 pi = pi* r^2
324 = r^2
18 = r
The hexagon = six equilateral triangles ....its area =
6 * √3 /4 * s^2 =
(3/2)√3 * 324 =
486√3 units^2
That looks great to me! In general, the formula for a hexagon is \(\frac{3\sqrt{3}}{2}s^2\) .