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Compute sum_{k = 2}^\infty (k - 3)/(k(k^2 - 1).

 Feb 10, 2020
 #1
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By telescoping sums, the sum is 2/7.

 Feb 10, 2020
 #2
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Thanks!

 Feb 10, 2020
 #3
avatar+29257 
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Hmm!  MathCad gives the following result:

 

 Feb 10, 2020

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