Find the discriminant of $3x^2 + \left(3 + \frac 13\right)x + \frac 13$.
\( 3x^2 + \left(3 + \frac 13\right)x + \frac 13\)
We can write this as
3x^2 + (10/3)x + 1/3
The discriminant is
(10/3)^2 - 4(3)(1/3) =
100/ 9 - 4 =
[ 100 - 36 ] / 9 =
64 / 9
+612 
