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A kayaker is traveling across a river at a velocity of 5 kilometers per hour. If the current is traveling at a rate of 2 kilometers per hour in a direction perpendicular to the kayaker's movement, what is the actual speed of the kayaker to the nearest hundredth? 

 Mar 9, 2020
 #1
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We can use the Pythagoean Theorem here.....the  effective speed is

 

sqrt ( 5^2  + 2^2)    =   sqrt (29)  ≈  5.39 km/h

 

 

cool cool cool

 Mar 9, 2020

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