Loading [MathJax]/jax/output/SVG/jax.js
 
+0  
 
0
602
1
avatar


Find the value of 53^3 using the identity (x + y)^3 = x^3 + 3x^2y + 3xy^2 + y^3.

Hint: 533 = (50 + 3)^3; therefore, x = 50 and y = 3

 

i would like to understand why the answer is what it is? please I dont get this

 Feb 8, 2016
 #1
avatar+2499 
0

 (x+y=53) just put any x and y whose sum is 53 and you wil get the same answer as533

(x+y)3=(x+y)(x+y)(x+y)=x3+3x2y+3xy2+y3

.
 Feb 8, 2016

2 Online Users

avatar