Find the value of 53^3 using the identity (x + y)^3 = x^3 + 3x^2y + 3xy^2 + y^3. Hint: 533 = (50 + 3)^3; therefore, x = 50 and y = 3
i would like to understand why the answer is what it is? please I dont get this
\(\text{ (x+y=53) just put any x and y whose sum is 53 and you wil get the same answer as} 53^3\)
\((x+y)^3=(x+y)(x+y)(x+y)=x^3 + 3x^2y + 3xy^2 + y^3\)
