+0  
 
0
421
1
avatar

Bottle A contains more soda than Bottle B. Pour from Bottle A into Bottle B as much soda as B already contains. Now pour from B into A as much soda as A now contains. Then pour from A into B as much soda as B now contains. Each bottle now contains 64 ounces. How many more ounces of soda were in Bottle A than Bottle B at the beginning?

 Jul 6, 2021
 #1
avatar+4 
+1

Let $a$ be the amount of soda contained by Bottle A and $b$ be the amount of soda contained by Bottle B. We can track the changes in amounts of soda in each bottle. First, Bottle A contains $a$ ounces, and Bottle B contains $b$. At the next step, A is reduced by $b$ ounces, and B gains $b$ ounces, so A has $a-b$ and B has $2b$ ounces. Then, A is increased by $a - b$ ounces and $B$ is reduced by the same, so A has $2a - 2b$ and B has $3b-a$ ounces. Finally, B is increased by $3b-a$ ounces and A is decreased by the same, so A has $3a - 5b$ ounces and B has $6b - 2a$ ounces. We are given that $3a - 5b = 6b - 2a = 64$, and we are looking for $a - b$. Adding $3a - 5b$ to $-2a + 6b$ gives $a + b = 128$. Adding $2a + 2b$ to $-2a + 6b$ gives $8b = 320$, or $b = 40$. So, $3a - 200 = 64$, or $a = 88$. Thus, $a - b = 88 - 40 = \boxed{48}$ ounces.

 Feb 14, 2022

2 Online Users

avatar
avatar