The sides of two regular octagons are 3 in. And 6 in. respectively. Find the ratio of their perimeters and their areas
Area of octagon 2 s^2 (1+sqr2)
3 : 2 (9)*(1+sqrt2) = 43.456 in2 perimeter =24 in per/area = .55228
6 in 2(36)(1+sqrt2)= 173.823 in2 perimeter =48 per/area =.27614
or marbe you want ratio per1/per2 area 1 / area2 I'll let you calc those (perimeter doubles area quadruples)