+0  
 
0
721
2
avatar

Find the number of real solutions to sin(x) = floor(x).

 Nov 19, 2019
 #1
avatar+33615 
+3

There are two.   When x=0 they both equal zero. When x=pi/2 they both equal 1. Larger values of x give floor(x)>sin(x);

smaller values of x give floor(x)

 Nov 19, 2019
edited by Alan  Nov 19, 2019
edited by Alan  Nov 19, 2019
 #2
avatar+33615 
+2

Odd!  That last line should have floor(x) < sin(x).

Alan  Nov 19, 2019

1 Online Users