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Find the number of real solutions to sin(x) = floor(x).

 Nov 19, 2019
 #1
avatar+28353 
+2

There are two.   When x=0 they both equal zero. When x=pi/2 they both equal 1. Larger values of x give floor(x)>sin(x);

smaller values of x give floor(x)

 Nov 19, 2019
edited by Alan  Nov 19, 2019
edited by Alan  Nov 19, 2019
 #2
avatar+28353 
+1

Odd!  That last line should have floor(x) < sin(x).

Alan  Nov 19, 2019

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