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# help

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Given an obtuse triangle ABC with $$\overline{AB}$$ past B to a point D such that  $$\overline{CD}$$ is perpendicular to  $$\overline{AB}$$ . Let F be the point on line segment  $$​​​​\overline{AC}$$ such that  $$\overline{BF}$$ is perpendicular to  $$\overline{AB}$$ , and extend  $$\overline{BF}$$ past F to a point E such that  $$​​\overline{BE}$$ is perpendicular to  $$\overline{CE}$$. Given that  $$\angle ECF = \angle BCD$$, show that  $$\triangle ABC \sim \triangle BFC$$ .

May 12, 2020