A weather balloon is launched from the ground at a spot 250 yards from a 65 foot royal palm tree. What is the minimal angle of elevation at which the balloon must take off in order to avoid hitting the tree? Assume that the balloon flies in a straight line and the angle of elevation stays constant.

Guest Jan 21, 2020

#1**+3 **

Right triangle

Hyptenuse is the flight path

One leg (opposite) is the tree 65 ft

Ohter leg is distance to tree 250 YARDS = 750 feet

Tan (angle ) = opposite/ adjacent = 65/750 I think you can take it from here!

ElectricPavlov Jan 21, 2020