Let \(a\) and \(b\) be the solutions of the equation \(2x^2-10x+5=0\). What is the value of \((2a-3)(4b-6)\)?
The solutions to 2x^2 - 10x + 5 = 0 are (5 +/- sqrt(15))/2 Plugging these values in, you get
(2*(5 + sqrt(15))/2 - 3)(4*(5 - sqrt(15))/2 - 6) = -18