The sum of three numbers in an arithmetic progression is 24 and their product is 440.What are the numbers?
+36916 a + a +d + a + 2d = 24
3a + 3d = 24
a + d = 8 d = 8-a
a (a+d)(a+2d) = 440
a (8)(a + 2d) =440
8a^2 +16ad = 440
8a^2 + 16(a)(8-a)
8a^2 + 128a -16a^2 -440 = 0
-8a^2 +128a-440 = 0 Quadratic Formula a = 5 or 11
results in 5 8 11
