The probability of Sanjeet hitting a target is 3/4. How many minimum number of times must he fire so that the probability of hitting the target of at least is more than 0.99?
+128406 This is impossible....if we call the number of shots, n....note that
(3/4)^n = (.75)^n will never = .99
The probability of Sanjeet hitting a target is 3/4. How many minimum number of times must he fire so that the probability of hitting the target of at least is more than 0.99?
Is something missing? Maybe "...the probability of hitting the target of at least one time is more than 0.99?"
Each individual time Sanjeet fires, his probability of hitting the target is always 0.75 each individual time.
Firing more than once will increase Sanjeet's probability of hitting the target, in regard to the total attempts.
Think about what would be the probability of Sanjeet not ever hitting the target, if he fired, oh say 100 times?
I think if Sanjeet fires twice, the probability of hitting the target is 0.75 + 0.75 = 1.5
Therefore he has to fire TWO TIMES to have a probability greater than 0.99 ...
note that even though this is a probability, it's still not a certainty.
I may be all wet here. A guy can go broke in a hurry betting against Chris.
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