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The probability of Sanjeet hitting a target is 3/4.  How many minimum number of times must he fire so that the probability of hitting the target of at least is more than 0.99?

 Dec 18, 2019
 #1
avatar+109563 
+1

This is impossible....if we call  the number of shots, n....note that

 

(3/4)^n    =  (.75)^n   will  never =  .99

 

 

 

cool cool cool    

 Dec 18, 2019
 #2
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0

 

The probability of Sanjeet hitting a target is 3/4.  How many minimum number of times must he fire so that the probability of hitting the target of at least is more than 0.99? 

 

Is something missing?  Maybe  "...the probability of hitting the target of at least one time is more than 0.99?" 


Each individual time Sanjeet fires, his probability of hitting the target is always 0.75 each individual time.

Firing more than once will increase Sanjeet's probability of hitting the target, in regard to the total attempts.

Think about what would be the probability of Sanjeet not ever hitting the target, if he fired, oh say 100 times?

I think if Sanjeet fires twice, the probability of hitting the target is 0.75 + 0.75 = 1.

Therefore he has to fire TWO TIMES to have a probability greater than 0.99 ...

note that even though this is a probability, it's still not a certainty. 

 

I may be all wet here.  A guy can go broke in a hurry betting against Chris. 

.

 Dec 18, 2019
 #3
avatar+29257 
+4

I think this is what the questioner might be looking for:

 

So 4 throws.

 Dec 18, 2019
 #4
avatar+109563 
0

Thanks, Alan  !!!!

 

 

cool cool cool

CPhill  Dec 18, 2019

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