The probability of Sanjeet hitting a target is 3/4. How many minimum number of times must he fire so that the probability of hitting the target of at least is more than 0.99?

Guest Dec 18, 2019

#1**+1 **

This is impossible....if we call the number of shots, n....note that

(3/4)^n = (.75)^n will never = .99

CPhill Dec 18, 2019

#2**0 **

*The probability of Sanjeet hitting a target is 3/4. How many minimum number of times must he fire so that the probability of hitting the target of at least is more than 0.99?*

Is something missing? Maybe "...the probability of hitting the target of at least **one time** is more than 0.99?"

Each individual time Sanjeet fires, his probability of hitting the target is always 0**.**75 each individual time.

Firing more than once will increase Sanjeet's probability of hitting the target, in regard to the __total__ attempts.

Think about what would be the probability of Sanjeet __not__ ever hitting the target, if he fired, oh say 100 times?

I think if Sanjeet fires twice, the probability of hitting the target is 0**.**75 + 0**.**75 = 1**.**5

Therefore he has to fire **TWO TIMES** to have a probability greater than 0**.**99 ...

note that even though this is a probability, it's still not a certainty.

I may be all wet here. A guy can go broke in a hurry betting against Chris.

_{.}

Guest Dec 18, 2019