what is the slope intercept form of a line that passes through (3,-5) and is perpendicular to y=3/2x+2
+23254 The slope of the line y = 3/2x + 2 is 3/2.
The slope of any line perpendicular to this line has a slope that is its negative reciprocal; the negative reciprocal is -2/3.
The point-slope form for a line is: y - y1 = m(x - x1).
For this problem, m = -2/3 x1 = 3 and y1 = -5.
Substituting, we get: y - -5 = (-2/3)(x - 3)
Simplifying: y + 5 = (-2/3)(x - 3)
Multiplying: y + 5 = (-2/3)x + 2
Adding 3 to both sides: y = (-2/3)x + 7
