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What is the equation of a circle with a center at (–2, 4) and a radius of 4?

Guest Feb 13, 2016

Best Answer 

 #1
avatar+2493 
+15

\((x-a)^2 + (y-b)^2 = r^2 \text{(equation of circle )}\)

 

where your:

a=-2      (x-a)^2=(x+2)^2

b=4        (y-b)^2=(y-4)^2

r=4         r^2=16

 

 

Here s your graph:

https://www.desmos.com/calculator/ivygaohoig

 

play with desmos and you will understand

Solveit  Feb 13, 2016
 #1
avatar+2493 
+15
Best Answer

\((x-a)^2 + (y-b)^2 = r^2 \text{(equation of circle )}\)

 

where your:

a=-2      (x-a)^2=(x+2)^2

b=4        (y-b)^2=(y-4)^2

r=4         r^2=16

 

 

Here s your graph:

https://www.desmos.com/calculator/ivygaohoig

 

play with desmos and you will understand

Solveit  Feb 13, 2016
 #2
avatar+93633 
0

Nice answer Solveit!

 

CPhill has nominated your answer here for the wrap.

That is a BIG compliment.        

 

Congratulations :)

Melody  Feb 14, 2016

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