What is the equation of a circle with a center at (–2, 4) and a radius of 4?

Guest Feb 13, 2016

#1**+15 **

\((x-a)^2 + (y-b)^2 = r^2 \text{(equation of circle )}\)

where your:

a=-2 (x-a)^2=(x+2)^2

b=4 (y-b)^2=(y-4)^2

r=4 r^2=16

Here s your graph:

https://www.desmos.com/calculator/ivygaohoig

play with desmos and you will understand

Solveit
Feb 13, 2016

#1**+15 **

Best Answer

\((x-a)^2 + (y-b)^2 = r^2 \text{(equation of circle )}\)

where your:

a=-2 (x-a)^2=(x+2)^2

b=4 (y-b)^2=(y-4)^2

r=4 r^2=16

Here s your graph:

https://www.desmos.com/calculator/ivygaohoig

play with desmos and you will understand

Solveit
Feb 13, 2016