For a certain value of , the system
\begin{align*}
x + y + 3z &= 10, \\
-4x + 2y + 5z &= 7, \\
kx + z &= 3
\end{align*}
has no solutions. What is this value of ?
+6248 \(\text{putting this into augmented matrix form}\\ \begin{pmatrix} 1&1&3&|&10\\ -4&2&5&|&7\\ k&0&1&|&3 \end{pmatrix}\)
\(\text{Now we row reduce this a bit}\\ \begin{pmatrix} 1&1&3&|&10\\ 0&6&17&|&47\\ 0&-k&1-3k&|&3-10k \end{pmatrix}\\ \begin{pmatrix} 1&1&3&|&10\\ 0&1&\frac{17}{6}&|&\frac{47}{6}\\ 0&0&1-\frac{k}{6}&|&3-\frac{10k}{6} \end{pmatrix}\)
\(\text{Now we see from the bottom row that if we let $k=6$ we have $0x+0y+0z = -7$}\\ \text{This is clearly impossible and thus $k=6$ is the number we are after}\)
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+26367 For a certain value of \(k\), the system
\(\begin{align*} x + y + 3z &= 10, \\ -4x + 2y + 5z &= 7, \\ kx + z &= 3 \end{align*}\)
has no solutions. What is this value of \(k\)?
answer see: https://web2.0calc.com/questions/help_12179
