how do you solve ln e^x =6
\(\begin{array}{rcll} \ln{ ( e^x ) } &=& 6 \\ x &=& 6 \end{array}\)
x=Log(6)/Log(2)
x=1.79176
I like to put in another step.
\(ln e^x =6\\ x*lne=6\\ x*1=6\\ x=6\)
