Container A and container B have leaks. Container A has 800ml of water and leaks 6ml per minute. Container B has 1000ml and leaks 10ml per minute. How many minutes will it take the two containers to have the same amount of water?
+36916 Amount in container a at time t is 800-6t
amount in container b is 1000-10t when are they equal?
800-6t = 1000-10t
4t = 200
t = 50 minutes
+36916 Amount in container a at time t is 800-6t
amount in container b is 1000-10t when are they equal?
800-6t = 1000-10t
4t = 200
t = 50 minutes
