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If we express 2x^2 + 6x + 11 in the form of a(x - h)^2 + k, then what is h?

 Apr 8, 2020
 #1
avatar+930 
+1

When written in vertex form, h= -1.5.

 

Hope this helps!

 

Edit: 
Step 1: Group the first 2 terms together, separating them from the constant term.


Step 2: Factor out leading coefficient, for completing the square to work, the coefficient of x^2 must be 1.


Step 3: Complete the square, Take half of x coefficient and square it. Notice to keep equation balanced you must add this number and subtract it making the net effect zero.


Step 4: Distribute and add constants.

So x-(-1.5) is the "h" you're looking for.

 

🔥🔥🔥

INFORMATION FROM: https://www.algebra.com/algebra/homework/quadratic/VertexFormSolver01.solver

 Apr 8, 2020
edited by HELPMEEEEEEEEEEEEE  Apr 8, 2020
edited by HELPMEEEEEEEEEEEEE  Apr 8, 2020
 #4
avatar+109519 
0

Thanks for the edit helpmeeeee.

 

Remember, partial answers and hints are always good.  :)

 

....So long as they come from someone who actually knows what they are talking about.

You have already earned credibility. I would assume you know how to answer in full if you wanted to.

I am referring to future answers, not this one.  laugh

Melody  Apr 11, 2020
 #2
avatar+109519 
0

Please do not give answers only.

We do not want to overtly encourage cheating and how is that supposed to help someone learn?

 

It is better to give partial answers.

 Apr 8, 2020
 #3
avatar+93 
0

Sometimes, a person isn't cheating: but that's rare. 

Nerdo  Apr 10, 2020

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