If we express 2x^2 + 6x + 11 in the form of a(x - h)^2 + k, then what is h?
When written in vertex form, h= -1.5.
Hope this helps!
Step 1: Group the first 2 terms together, separating them from the constant term.
Step 2: Factor out leading coefficient, for completing the square to work, the coefficient of x^2 must be 1.
Step 3: Complete the square, Take half of x coefficient and square it. Notice to keep equation balanced you must add this number and subtract it making the net effect zero.
Step 4: Distribute and add constants.
So x-(-1.5) is the "h" you're looking for.
Thanks for the edit helpmeeeee.
Remember, partial answers and hints are always good. :)
....So long as they come from someone who actually knows what they are talking about.
You have already earned credibility. I would assume you know how to answer in full if you wanted to.
I am referring to future answers, not this one.