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# help

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If we express 2x^2 + 6x + 11 in the form of a(x - h)^2 + k, then what is h?

Apr 8, 2020

#1
+930
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When written in vertex form, h= -1.5.

Hope this helps!

Edit:
Step 1: Group the first 2 terms together, separating them from the constant term.

Step 2: Factor out leading coefficient, for completing the square to work, the coefficient of x^2 must be 1.

Step 3: Complete the square, Take half of x coefficient and square it. Notice to keep equation balanced you must add this number and subtract it making the net effect zero.

Step 4: Distribute and add constants.

So x-(-1.5) is the "h" you're looking for.

🔥🔥🔥

Apr 8, 2020
edited by HELPMEEEEEEEEEEEEE  Apr 8, 2020
edited by HELPMEEEEEEEEEEEEE  Apr 8, 2020
#4
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Thanks for the edit helpmeeeee.

Remember, partial answers and hints are always good.  :)

....So long as they come from someone who actually knows what they are talking about.

You have already earned credibility. I would assume you know how to answer in full if you wanted to.

I am referring to future answers, not this one.

Melody  Apr 11, 2020
#2
+109519
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We do not want to overtly encourage cheating and how is that supposed to help someone learn?

It is better to give partial answers.

Apr 8, 2020
#3
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Sometimes, a person isn't cheating: but that's rare.

Nerdo  Apr 10, 2020