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Suppose f is a polynomial such that f(0) = 47, f(1) = 32, f(2) = -13, and f(3)=16. What is the sum of the coefficients of f?

 Aug 23, 2019
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Since  f(0)  = 47.....then the constant term of the polynomial  = 47

 

And since  f(1)  = 32   then we have that

 

[ sum of coefficients ] + 47  =  32        subtract 47 from both sides

 

[ sum of coefficients ]  =  32 - 47  =   -15

 

 

cool cool cool

 Aug 23, 2019

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