We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
308
1
avatar

A portion of the graph of a quadratic function $f(x)$ is shown below.  Let $g(x)=-f(x)$ and $h(x)=f(-x)$. If $a$ is the number of points where the graphs of $y=f(x)$ and $y=g(x)$ intersect, and $b$ is the number of points where the graphs of $y=f(x)$ and $y=h(x)$ intersect, then what is $10a+b$?

 Jul 24, 2018
 #1
avatar+99659 
+1

g(x) = -f(x)  will "flip" the graph of f(x) over the  x axis.....it will intersect with f(x)  in two places - at the points where f(x)  intersects the  x axis...so  "a"  = 2

 

h(x)  = f(-x) will  "flip" the graph of f(x) across the  y axis..it wil intersect with  f(x)  in one place - at the point where f(x) intersects the y axis...so...."b" = 1

 

So  10a + b  =   10(2) + 1  =   20 + 1   = 21

 

 

cool cool cool

 Jul 24, 2018

11 Online Users

avatar
avatar