+373 Hey there, Guest!
You prob already saw EP's answer; I agree, you could use a calculator, but I'll walk you step-by-step through this instead.
\(30^3=27000\rightarrow\)\(\sqrt[3]{27000+40^3+50^3}\)
\(40^3=64000\rightarrow\)\(\sqrt[3]{27000+64000+50^3}\)
\(50^3=125000\rightarrow\)\(\sqrt[3]{27000+64000+125000}\)
\(\mathrm{Add\:the\:numbers:}\:27000+64000+125000=216000\rightarrow\)\(\sqrt[3]{216000}\)
\(\mathrm{Factor\:the\:number:\:}\:216000=60^3\rightarrow\)\(\sqrt[3]{60^3}\)
\(\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a\) and then we get our answer, 60.
Hope this helped! :)
( ﾟдﾟ)つ Bye
