Compute\( \sqrt{1^3 + 2^3 + 3^3 + \dots + 100^3}\)
The sum of 13 + 23 + 33 + ... + n3 = [ n2·(n + 1)2 ] / 4
So: the sum of 13 + 23 + 33 + ... + 1003 = [ 1002·(100 + 1)2 ] / 4 = 25502500
I'll let you find the square root.
