+0  
 
0
33
1
avatar

Compute\( \sqrt{1^3 + 2^3 + 3^3 + \dots + 100^3}\)

 May 14, 2020
 #1
avatar+20906 
0

The sum of 13 + 23 + 33 + ... + n3  =  [ n2·(n + 1)2 ] / 4

 

So:  the sum of 13 + 23 + 33 + ... + 1003  =  [ 1002·(100 + 1)2 ] / 4  =  25502500

 

I'll let you find the square root.

 May 14, 2020

14 Online Users

avatar