Set L contains exactly four consecutive, positive, odd integers. The sum of the greatest integer and twice the least integer is 39. What is the least integer in the set?
Let the least integer = 2n - 1
Let the greatest integer = 2n + 5
So
(2n + 5) + 2 (2n - 1) = 39 simplify
6n + 3 = 39
6n = 36
n = 6
The least integer is 2(6) - 1 = 11
