Peter had 5/6 as many jellybeans as Chase. When Chase gave 1/2 of his jellybeans to Peter, he then had 55 fewer jellybeans than his friend. How many jellybeans did Chase have at first?
+237 Let Chase had jellybeans = x
Peter had jellybeans = 5/6 of x
= 5x/6
Chase gave jellybeans to Peter = 1/2 of x
= x/2
Now Chase had jellybeans = x - x/2
= x/2
Now Peter had jellybeans = 5x/6 + x/2
According to problem
5x/6 + x/2 = x/2 + 55
5x/5 + x/2 - x/2 = 55
5x/6 = 55
x = (55 * 6)/5
x = 66
Chase had jellybeans at first = 66
