Peter had 5/6 as many jellybeans as Chase. When Chase gave 1/2 of his jellybeans to Peter, he then had 55 fewer jellybeans than his friend. How many jellybeans did Chase have at first?

Guest May 22, 2022

#1**+1 **

Let Chase had jellybeans = x

Peter had jellybeans = 5/6 of x

= 5x/6

Chase gave jellybeans to Peter = 1/2 of x

= x/2

Now Chase had jellybeans = x - x/2

= x/2

Now Peter had jellybeans = 5x/6 + x/2

According to problem

5x/6 + x/2 = x/2 + 55

5x/5 + x/2 - x/2 = 55

5x/6 = 55

x = (55 * 6)/5

x = 66

Chase had jellybeans at first = 66

Slimesewer May 23, 2022