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Peter had 5/6 as many jellybeans as Chase. When Chase gave 1/2 of his jellybeans to Peter, he then had 55 fewer jellybeans than his friend. How many jellybeans did Chase have at first?

 May 22, 2022
 #1
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Let Chase had jellybeans = x

Peter had jellybeans = 5/6 of x

                                  = 5x/6

Chase gave jellybeans to Peter = 1/2 of x

                                               = x/2

Now Chase had jellybeans = x - x/2

                                           = x/2

Now Peter had jellybeans = 5x/6 + x/2

According to problem

                5x/6 + x/2 = x/2 + 55

                5x/5 + x/2 - x/2 = 55

                     5x/6 = 55

                          x = (55 * 6)/5

                          x = 66

Chase had jellybeans at first = 66

 May 23, 2022

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