+24 Sixteen metres of fencing are available to enclose a rectangular garden.
Represent the area of the garden as a function of the length of the one side.
What dimensions provide an area greater than 12m^2?
+15131 Sixteen metres of fencing are available to enclose a rectangular garden.
Represent the area of the garden as a function of the length of the one side.
\(A=l\times b\\b=\frac{z-2l}{2}\\b=\frac{14m-2l}{2}\)
\(A=f(l)=l\times (7m-l)=l\times 7m-l^2\)
\(A=f(l)=l\times 7m-l^2\)
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+130514
Let one side = x
The......the other side = (16 - 2x) / 2 = 8 - x
And the area, A(x), can be represented as
A ( x) = x ( 8 - x) = -x^2 + 8x
To find out the dimensions that would make the area > 12 m^2 we have
-x^2 + 8x > 12
Look at the graph, here : https://www.desmos.com/calculator/umwcrycnrg
It shows that the area will be greater than 12m^2 when 2 m < x < 6 m
