help

We are asking ourselves.....where  does  the sin  = -√3/2  ?

This  is  a  60°  angle  in  the  4th quadrant    =   - pi / 3   (or   -60°  )

What is the value of sin^-1 (−√3/2) ?

Hello Guest!

\(sin^{-1}(-\sqrt{\frac{3}{2}}\ )= \frac{1}{sin(- \sqrt{\frac{3}{2}}\cdot \frac{180^o}{\pi}\ )}=\frac{1}{\color{blue}sin(-70.17^o)}=-1.063\)

  !