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For what real values of s is 9x^2 + sx + 4 the square of a binomial?

 Jun 27, 2020
 #1
avatar+26735 
+1

(3x   +  2  )^2  =  9x^2 + 12x + 4                           s = 12 

 Jun 27, 2020
 #2
avatar+8341 
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s = -12 is also a solution.

MaxWong  Jun 28, 2020
 #3
avatar+8341 
0

Square of binomial <=> Discriminant = 0

 

\(s^2 - 4(9)(4) = 0\\ s^2 = 144\\ s = \pm12\)

 Jun 28, 2020

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