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What is the polar form of the equation?

x^2+(y+5)^2=25

 Apr 30, 2020
 #1
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x^2 + ( y + 5)^2  = 25

 

x = r cos θ

y = r sin θ

 

So we have

 

(r cos θ)^2  +  (r sin θ + 5)^2  =  25

 

r^2 cos^2 θ  +  r^2 sin^2 θ  + 10r sin θ + 25  = 25

 

r^2  ( cos ^2 θ  + sin^2 θ ) + 10rsin θ =  0

 

r^2  ( 1)  +  10r sin θ  =  0      

 

r^2  + 10r sin θ  =  0           divide out r

 

r +10 sin θ =  0

 

r = -10 sin θ

 

 

cool cool cool

 Apr 30, 2020

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