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Help.

NotSoSmart  Nov 16, 2017
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 #1
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+1

x^2 - 7x  -  6  = 0

 

Let   a  =1, b =  -7   and c =  -6

 

The "formula" is

 

[ - b ±√ [ b^2 - 4ac]  ]  /  [2a]

 

Filling in the missing pieces, we have

 

[ - (-7) ±√ [ (-7)^2 - 4 (1)(-6) ] / [ 2(1) ]

 

[ 7 ±√ [ 49 + 24 ] ]  / 2

 

[ 7 ±√ 73 ] / 2

 

So...the two solutions are

 

[ 7 +√ 73 ] / 2     and  [ 7 -√ 73 ] / 2

 

 

cool cool cool

CPhill  Nov 16, 2017

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