Find the vertex of the parabola x = -2y^2 + 12y - 15.
x = –2y2 + 12y – 15
1st derivative –4y + 12
set = 0 –4y + 12 = 0
–4y = –12
y = +3
sub 3 for y x = –2(9) + 12(3) – 15
x = –18 + 36 – 15
x = –33 + 36
x = +3
Vertex at (3, 3)
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