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\( \frac{\sqrt x}{\sqrt y}\\\frac{ {\left( \frac{1}{2} \right)}^2 + {\left( \frac{1}{3} \right)}^2 }{ {\left( \frac{1}{4} \right)}^2 + {\left( \frac{1}{5} \right)}^2} = \frac{13x}{41y} \)

 

 

(The LaTeX is as above)

 

Express $\sqrt{x} \div\sqrt{y}$ as a common fraction, given: $\frac{ {\left( \frac{1}{2} \right)}^2 + {\left( \frac{1}{3} \right)}^2 }{ {\left( \frac{1}{4} \right)}^2 + {\left( \frac{1}{5} \right)}^2} = \frac{13x}{41y} $

 

Express sqrt(x) divided by sqrt(y) given that:(use latex)

 Feb 16, 2019
edited by Alan  Feb 17, 2019
edited by Guest  Feb 17, 2019
 #1
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+2

Could you make it clearer? Im kind of stunned.

I will try to fix it, but I might mess up the problem.

Your problem:

Express           square root of x                                                  

                        ---------------------   as a common fraction. given  (1/2)^2+ (1/3)^2+(1/4)^2+(1/5)^2=13x/41y

                        square root of y                                                  

Let us just work with the (1/2)^2+ (1/3)^2+(1/4)^2+(1/5)^2 first

1/4 + 1/9 + 1/16 + 1/25

common denominator 3600

900+400+225+144      1669

------------------------- =  ---------

       3600                      3600

 

31x     1669

----- = -------- We want to find x/y first so we can square root afterward.

41y     3600

Divide by 31 on both sides gives x/41y = 1669/111600

Multiplying 41 on both sides gives x/y = 68429/111600

Now we can square root it,  finding sqrt(68429)/60 times the square root of 31

 

I might of done this problem wrong, but hopefully this helps.

To the moderators-Is there something wrong with the latex system on this site?

 Feb 17, 2019

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