\( \frac{\sqrt x}{\sqrt y}\\\frac{ {\left( \frac{1}{2} \right)}^2 + {\left( \frac{1}{3} \right)}^2 }{ {\left( \frac{1}{4} \right)}^2 + {\left( \frac{1}{5} \right)}^2} = \frac{13x}{41y} \)
(The LaTeX is as above)
Express $\sqrt{x} \div\sqrt{y}$ as a common fraction, given: $\frac{ {\left( \frac{1}{2} \right)}^2 + {\left( \frac{1}{3} \right)}^2 }{ {\left( \frac{1}{4} \right)}^2 + {\left( \frac{1}{5} \right)}^2} = \frac{13x}{41y} $
Express sqrt(x) divided by sqrt(y) given that:(use latex)
+367 Could you make it clearer? Im kind of stunned.
I will try to fix it, but I might mess up the problem.
Your problem:
Express square root of x
--------------------- as a common fraction. given (1/2)^2+ (1/3)^2+(1/4)^2+(1/5)^2=13x/41y
square root of y
Let us just work with the (1/2)^2+ (1/3)^2+(1/4)^2+(1/5)^2 first
1/4 + 1/9 + 1/16 + 1/25
common denominator 3600
900+400+225+144 1669
------------------------- = ---------
3600 3600
31x 1669
----- = -------- We want to find x/y first so we can square root afterward.
41y 3600
Divide by 31 on both sides gives x/41y = 1669/111600
Multiplying 41 on both sides gives x/y = 68429/111600
Now we can square root it, finding sqrt(68429)/60 times the square root of 31
I might of done this problem wrong, but hopefully this helps.
To the moderators-Is there something wrong with the latex system on this site?
