Find $$\sum_{k = 0}^{10} (k + 2) \cdot 3 \cdot 2^k.$$\(Find $$\sum_{k = 0}^{10} (k + 2) \cdot 3 \cdot 2^k.$$\)
Find $$\sum_{k = 0}^{10} (k + 2) \cdot 3 \cdot 2^k.$$
\(\displaystyle \sum \limits_{k = 0}^{10} (k + 2) \cdot 3 \cdot 2^k = 33 \cdot 2^{11} = 67584\)
