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Suppose that a is inversely proportional to b. Let a1,a2 be two nonzero values of a such that {a1}/{a2}={2}/{3}. Let the corresponding b values be b1,b2. If b1,b2 are nonzero, find the value of {b1}/{b2}

 Apr 30, 2019
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a = k *1/b
2/3 =k * 1/b1 /k * 1/b2 [k = constant cacels out]
2/3 =1/b1 * b2
2/3 = b2/b1
b1 =3 and 
b2 =2. Therefore:
b1/b2 =3/2. Another way of looking at it, is this:
When a1 =2, b1=1/2
When a2 =3, b2=1/3
So, when a1/a2 = 2/3, then:
b1/b2 =(1/2) / (1/3) =(1/2) x (3/1)
          =3/2

 Apr 30, 2019

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