Suppose that a is inversely proportional to b. Let a1,a2 be two nonzero values of a such that {a1}/{a2}={2}/{3}. Let the corresponding b values be b1,b2. If b1,b2 are nonzero, find the value of {b1}/{b2}

a = k *1/b 2/3 =k * 1/b1 /k * 1/b2 [k = constant cacels out] 2/3 =1/b1 * b2 2/3 = b2/b1 b1 =3 and b2 =2. Therefore: b1/b2 =3/2. Another way of looking at it, is this: When a1 =2, b1=1/2 When a2 =3, b2=1/3 So, when a1/a2 = 2/3, then: b1/b2 =(1/2) / (1/3) =(1/2) x (3/1) =3/2