Carmelo is selling his hockey and baseball card collection. Hockey cards, x, sell for $0.03 and baseball cards, y, sell for $0.05. The number of hockey cards Carmelo sells is at least six times the number of baseball cards he sells. He has at most 525 cards to sell.

What is the maximum revenue he can make?

$15.75

$17.25

$26.25

$28.50

Guest Aug 31, 2018

#1**+1 **

Let x be the number of hockey cards he sells and y be the number of baseball cards he sells ....so we have these inequalities

x ≥ 6y

x + y ≤ 525

And we wish to maximize this objective revenue function, R

R = .03x + .05y

Here's the graph of the inequalities : https://www.desmos.com/calculator/h7qwjcc9g2

It can be shown that the max revenue occurs at the corner point (x, y) = (450, 75)

So...the max revenue is

.03(450) + .05(75) = $17.25

CPhill
Aug 31, 2018