+0  
 
+1
111
2
avatar+436 

Find the unique four-digit integer n with these properties:

 The last digit (the units digit) of n is 9.

 The digits of n add up to 27.

 Two digits of n are the same.

 n is a perfect square.

SmartMathMan  Jan 26, 2018
 #1
avatar
+2

63^2 = 3,969  Meets ALL the conditions.

Guest Jan 26, 2018
 #2
avatar+92623 
+2

If x^2 ends in 9 then the x must end in 3 or 7

If x^2 is four digits then x must be between 32 and 99

 

So the only possibilities for x are

33, 37, 43, 47, 53, 57, 63, 67, 73, 77, 83, 87, 93, 97

 

Square each of those and find the one/s that fit the other two requirements :)

Melody  Jan 26, 2018

10 Online Users

avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.