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Can you help please ;)

 May 9, 2021
 #1
avatar+34340 
+2

Note that angle  r  and angle  t   encompass the entire 360 degree circumference

  remember that inscribed angles inercept arcs 2 times the angle

so [  3x +5       +    5x +15 ] * 2 = 360      now you can solve for x    and can label three of the angles

 

Then ...all of the angles sum to 360 degrees

     can you solve for q  now ?

 May 9, 2021
 #2
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0

I'll try...

Angle TQR = 180 - (160/8 * 4 +30)

Guest May 9, 2021
 #3
avatar+114485 
+1

All you need to know is that

 

Opposite angles in a cyclic quad are supplementary.

 May 10, 2021
 #4
avatar+34340 
+1

Yeppers....THAT is much easier!   

ElectricPavlov  May 10, 2021
 #5
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+1

Does that mean 5x+15 = 3x+5?

Guest May 10, 2021
 #6
avatar+114485 
+1

no, supplementary angles add to 180 degrees

so it means

 

3x+5   +    5x+15 = 180

Melody  May 10, 2021
 #7
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+1

ohh i understand, thanks!

Guest May 10, 2021

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