Determine \(\sum_{n = 2}^\infty \frac{4n^3 - n^2 - n + 1}{n^6 - n^5 + n^4 - n^3 + n^2 - n}.\)
By partial fractions, the sum works out to 2.
∑[(4 n^3 - n^2 - n + 1)/(n^6 - n^5 + n^4 - n^3 + n^2 - n)], n, 2, ∞ =converges to 1
